Alexander to Stay in Seattle
From the Associated Press
SEATTLE — NFL most valuable player Shaun Alexander has agreed to a $62-million, eight-year contract to remain with the Seattle Seahawks, his agent said Sunday night.
Jim Steiner said the deal is the richest for any NFL running back and will pay the league’s leading rusher more than $15.1 million in guaranteed cash, through signing and other bonuses and 2006 base salary.
The league still must approve the contract, and Alexander has yet to sign it. The team is waiting for the contract to become official before announcing the deal.
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